Probability is the branch of mathematics that deals with the study of chance and uncertainty.
It tells us how likely an event is to occur.
We use probability to describe situations where we are not certain about the outcome — for example:
In short, probability measures how likely or unlikely something is to happen.
The probability of an event is given by:
P(E) = Number of favourable outcomes / Total number of possible outcomes
Where:
| Event Type | Meaning | Probability |
|---|---|---|
| Impossible | Cannot happen | 0 |
| Unlikely | May not happen | Between 0 and 0.5 |
| Even Chance | Can happen or not happen | 0.5 |
| Likely | Expected to happen | Between 0.5 and 1 |
| Certain | Must happen | 1 |
0 means the event will never happen.
1 means the event will definitely happen.
Values between 0 and 1 show how likely it is.
Problem: Over the last 10 days it rained on 7 days. If you pick one of those days at random, what is the probability it was a rainy day?
Steps:
Total days = 10.
Favourable (rain) = 7.
Probability = 7 ÷ 10 = 7/10.
As a percent = 70%.
Answer: 7/10 (70%).
Problem: In a class of 40 students, 28 passed English. If the teacher picks one student at random, what is the probability the student passed English?
Steps:
Total students = 40.
Favourable (passed English) = 28.
Probability = 28 ÷ 40 = divide by 4 → 7 ÷ 10 = 7/10.
Percent = 70%.
Answer: 7/10 (70%).
Problem: The school team played 12 matches this season: they won 7, drew 3, lost 2. What is the probability that a randomly chosen match was a win?
Steps:
Total matches = 12.
Favourable (win) = 7.
Probability = 7 ÷ 12 → 7/12 ≈ 58.3%.
Answer: 7/12 (≈58.3%).
Problem: A trader has 50 tomatoes; 15 are rotten and 35 are good. If you pick one tomato without looking, what is the probability it is good?
Steps:
Total tomatoes = 50.
Favourable (good) = 35.
Probability = 35 ÷ 50 = divide by 5 → 7 ÷ 10 = 7/10.
Answer: 7/10 (70%).
Problem: A commuter notes that in 20 days the local bus arrived late on 5 days. If we choose one of those 20 days at random, what is the probability the bus was on time?
Steps:
Total days = 20.
Favourable (on time) = 20 − 5 = 15.
Probability = 15 ÷ 20 = 3 ÷ 4 = 3/4 = 75%.
Answer: 3/4 (75%).
Problem: A seller has 20 puff-puffs: 8 plain, 7 sugar-coated, 5 banana. You pick one. What is the probability it is sugar-coated?
Steps:
Total = 20.
Favourable (sugar-coated) = 7.
Probability = 7 ÷ 20 = 7/20 = 35%.
Answer: 7/20 (35%).
Problem: The school library shelf has 3 Maths textbooks, 2 English, and 5 story books. A student takes one book at random. What is the probability it is a story book?
Steps:
Total books = 3 + 2 + 5 = 10.
Favourable (story) = 5.
Probability = 5 ÷ 10 = 1/2 = 50%.
Answer: 1/2 (50%).
Problem: In JSS3, 60 students were asked about their preferred stream: 35 picked Arts, 25 picked Science. What is the probability a student chosen at random picked Science?
Steps:
Total students = 60.
Favourable (Science) = 25.
Probability = 25 ÷ 60 = divide by 5 → 5 ÷ 12 = 5/12 ≈ 41.7%.
Answer: 5/12 (≈41.7%).
Problem: A school sells 100 raffle tickets and will draw 3 winning tickets. If you buy one ticket, what is the probability you win at least one prize?
Steps:
Total tickets = 100. Number of winners = 3.
Probability = 3 ÷ 100 = 3/100 = 0.03 = 3%.
Answer: 3/100 (3%).
Problem: A box has 3 mangoes, 4 oranges, 3 apples (total 10 fruits). You pick 2 fruits one after the other without replacement. What is the probability both picked are apples?
Steps:
Total fruits = 10. Favourable first pick (apple) = 3.
P(first apple) = 3 ÷ 10.
After one apple is taken, apples left = 2, total left = 9.
P(second apple | first apple) = 2 ÷ 9.
Multiply: P(both apples) = (3/10) × (2/9) = 6 ÷ 90 = 1 ÷ 15 = 1/15 ≈ 6.67%.
Answer: 1/15 (≈6.67%).
Problem: At a club fair, 30 students like football, 20 like basketball, and 10 like both sports. If a student is chosen at random from the group, what is the probability they like football or basketball?
Steps:
P(Football or Basketball) = P(F) + P(B) − P(F and B)
Total unique students = 30 + 20 − 10 = 40.
P(F) = 30 ÷ 40 = 3/4.
P(B) = 20 ÷ 40 = 1/2.
P(F and B) = 10 ÷ 40 = 1/4.
P(F or B) = 3/4 + 1/2 − 1/4 = 1 (100%).
Answer: 1 (100%).
Problem: In a class of 30, 18 brought books and 12 did not. The teacher picks one student at random who brought books for a prize. What is the probability the picked student brought books?
Steps:
Total students = 30. Favourable (brought books) = 18.
Probability = 18 ÷ 30 = divide by 6 → 3 ÷ 5 = 3/5 = 60%.
Answer: 3/5 (60%).
Problem: A small survey found 60% of commuters use bus card A. If you meet one commuter at random, what is the probability they use bus card A?
Steps:
Percent 60% = 60 ÷ 100 = 0.60.
As fraction = 60/100 = 3/5.
Probability = 3/5 (0.6 or 60%).
Answer: 3/5 (60%).
Problem: The canteen sells 4 types of drinks; yesterday 40 cartons were sold: 10 cola, 12 malt, 8 juice, 10 water. If you pick one sold carton at random, what is the probability it is not juice?
Steps:
Total = 40. Favourable (not juice) = 40 − 8 = 32.
Probability = 32 ÷ 40 = divide by 8 → 4 ÷ 5 = 4/5 = 80%.
Answer: 4/5 (80%).
Problem: A jar has 6 red and 4 blue marbles. You draw one marble, note the colour, put it back, then draw again. What is the probability both draws are red?
Steps:
Since we replace, probabilities do not change between draws.
P(red on first) = 6 ÷ 10 = 3/5.
P(red on second) = 3/5.
Multiply: (3/5) × (3/5) = 9/25 = 36%.
Answer: 9/25 (36%).
When a coin is tossed:
Sample space = {Head (H), Tail (T)}
Total outcomes = 2
Favourable outcomes for Head = 1
P(Head) = 1 ÷ 2 = 1/2
Similarly,
P(Tail) = 1 ÷ 2 = 1/2
When a die is rolled:
Sample space = {1, 2, 3, 4, 5, 6}
If we want the probability of getting an even number:
Favourable outcomes = {2, 4, 6} → 3 outcomes
P(Even number) = 3 ÷ 6 = 1/2
A box contains 5 red balls, 3 blue balls, and 2 green balls.
Find the probability of picking:
Solution:
Total number of balls = 5 + 3 + 2 = 10
(i) Favourable outcomes for red = 5
P(Red) = 5 ÷ 10 = 1/2
(ii) Favourable outcomes for green = 2
P(Green) = 2 ÷ 10 = 1/5
Sample space = {1, 2, 3, 4, 5, 6}
Favourable outcome = {3}
Total outcomes = 6
P(3) = 1 ÷ 6
The value of probability is always between 0 and 1.
| Probability | Meaning | Example |
|---|---|---|
| 0 | Impossible event | Getting 8 when rolling a die |
| 1/2 | Equal chance | Getting Head or Tail |
| 1 | Certain event | Getting a number less than 7 on a die |
If the probability of an event happening is P(E), then the probability of it not happening is:
P(not E) = 1 - P(E)
Example: If P(getting a head) = 1/2, then
P(not getting a head) = 1 - 1/2 = 1/2
A bag contains 4 white balls and 6 black balls. If one ball is picked at random, find:
Solution:
Total balls = 4 + 6 = 10
(a) P(White) = 4/10 = 2/5
(b) P(Black) = 6/10 = 3/5
A box contains 2 red, 3 green, and 5 blue balls. If a ball is selected at random, find the probability that it is:
Solution:
Total = 2 + 3 + 5 = 10
(a) P(Red) = 2/10 = 1/5
(b) Not blue → Red or Green = 2 + 3 = 5
P(Not blue) = 5/10 = 1/2
A die is thrown once. Find the probability of getting:
Solution:
Sample space = {1, 2, 3, 4, 5, 6}
(a) Prime numbers = {2, 3, 5} → 3 outcomes
P(Prime) = 3/6 = 1/2
(b) Numbers greater than 4 = {5, 6} → 2 outcomes
P(Greater than 4) = 2/6 = 1/3
A coin is tossed twice. Find the probability of getting:
Solution:
Sample space = {HH, HT, TH, TT} → 4 outcomes
(a) Two heads = {HH} → 1 outcome
P(Two heads) = 1/4
(b) One head = {HT, TH} → 2 outcomes
P(One head) = 2/4 = 1/2