An angle is the amount of turning or rotation between two straight lines that meet at a point. The point where the two lines meet is called the vertex, and the lines themselves are called the arms or sides of the angle.
In simple words, an angle measures how much one line turns away from another around a point.
Arm 1
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\
\
\
\ ← Angle
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B-----------C
↑
Vertex
Here, ∠ABC is the angle, B is the vertex, and BA and BC are the arms.
An angle is formed when two straight lines meet at a point or when one straight line turns about a fixed point. It is measured in degrees (°).
If a door turns about its hinge, the hinge is the vertex, the sides of the door are the arms, and the space opened by the door is the angle.
The standard unit for measuring an angle is the degree (°). There are:
Full circle = 360° Half circle = 180° Quarter circle = 90°
A protractor is used to measure or draw angles in degrees. It is a semicircular or circular instrument marked from 0° to 180° or 0° to 360°.
Arm 1
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Vertex (O)
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Arm 2
Angles are classified according to their sizes.
Definition: An acute angle is an angle less than 90°. It is smaller than a right angle.
Examples: 25°, 40°, 60°
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Real-life examples: The tip of a slice of pizza; the corner of a road turning sharply.
Definition: A right angle is an angle exactly equal to 90°. It forms a perfect corner — like the corner of a square or a book.
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Real-life examples: The corner of a wall; the corner of a sheet of paper.
Definition: An obtuse angle is an angle that is greater than 90° but less than 180°. It is wider than a right angle.
Examples: 120°, 135°
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Real-life examples: The angle formed when you open a door wide; the slant of a hill.
Definition: A straight angle is exactly 180°. It looks like a straight line. It is equal to two right angles combined.
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Real-life examples: The top edge of a ruler; the horizon line where the sky meets the earth.
Definition: A reflex angle is an angle greater than 180° but less than 360°. It looks like a large opening or turning beyond a straight line.
Examples: 220°, 300°
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\_________
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Real-life examples: The turning of a clock hand from 12 to 8; the wide opening of a car door.
Definition: A complete angle or full rotation is exactly 360°. It represents a full turn around a point.
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\ ___ /
Real-life examples: The second hand of a clock making a full circle; the wheel of a car turning one complete round.
Two angles are complementary if their sum is 90°.
Example: 30° and 60° are complementary (30° + 60° = 90°).
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Two angles are supplementary if their sum is 180°.
Example: 70° and 110° are supplementary (70° + 110° = 180°).
When two straight lines cross each other, the opposite angles are equal.
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X
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If the lines intersect, the pairs of opposite angles formed are equal.
Two angles that share a common vertex and one common arm, but do not overlap, are called adjacent angles.
Angles that lie on a straight line add up to 180°.
A------B------C
∠ABD + ∠DBC = 180°
The sum of all angles around a point = 360°.
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---O---
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When two parallel lines are cut by another line (called a transversal), certain angles are formed:
A---------B
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\ /
X
/ \
/ \
C---------D
Here, AB ∥ CD and the slanting line is the transversal.
Angles can be constructed (drawn) and bisected (divided into two equal parts) using:
Steps:
Steps:
| Property | Description | Total |
|---|---|---|
| Angles on a straight line | Sum of angles = 180° | 180° |
| Angles at a point | Sum of angles = 360° | 360° |
| Angles in a triangle | Sum of angles = 180° | 180° |
| Angles in a quadrilateral | Sum of angles = 360° | 360° |
| Vertically opposite angles | Equal | — |
| Alternate and corresponding angles | Equal when lines are parallel | — |
A polygon is a closed plane figure made up of three or more straight sides joined end to end.
Each polygon is named according to the number of sides it has.
| Name of Polygon | Number of Sides | Example |
|---|---|---|
| Triangle | 3 | ΔABC |
| Quadrilateral | 4 | Square, Rectangle |
| Pentagon | 5 | Regular pentagon |
| Hexagon | 6 | Regular hexagon |
| Heptagon | 7 | Regular heptagon |
| Octagon | 8 | Regular octagon |
| Nonagon | 9 | — |
| Decagon | 10 | — |
Triangle (3 sides):
/\ /__\
Quadrilateral (4 sides):
______ | | |______|
Pentagon (5 sides):
/\ / \ /____\ \ / \__/
Regular Polygon: All sides and all angles are equal (e.g., square, regular hexagon).
Irregular Polygon: Sides and angles are not all equal (e.g., a rectangle or any uneven shape).
Interior angles are inside the polygon.
Exterior angles are outside the polygon, formed by extending one side.
Diagram (for one vertex of a polygon):
/
/|
/_|
(inside)
The inner part (inside) = interior angle
The outer part (outside) = exterior angle
A polygon can be divided into triangles by drawing diagonals from one vertex.
Since the sum of angles in one triangle = 180°, and the polygon can be divided into (n − 2) triangles,
Sum of interior angles = (n − 2) × 180°
where n = number of sides.
Quadrilateral (4 sides):
A------B | /| | / | | / | C------D
From vertex A, one diagonal (AC) divides the quadrilateral into 2 triangles.
Hence, Sum of angles = (4 − 2) × 180° = 2 × 180° = 360°.
For a Pentagon (5 sides):
A / \ B---E | / | / C-D
From vertex A, diagonals divide the shape into 3 triangles.
Therefore: Sum of angles = (5 − 2) × 180° = 3 × 180° = 540°.
If the polygon is regular (all angles equal):
Each interior angle = ((n − 2) × 180°) ÷ n
Example 1: Find the sum of the interior angles of a hexagon.
Solution: n = 6
Sum = (6 − 2) × 180° = 4 × 180° = 720°
Example 2: Find each interior angle of a regular pentagon.
Solution: n = 5
Each = [(5 − 2) × 180°] ÷ 5 = (3 × 180°) ÷ 5 = 540° ÷ 5 = 108°
Example 3: Find the sum of the interior angles of a decagon.
Solution: n = 10
Sum = (10 − 2) × 180° = 8 × 180° = 1440°
At each vertex of a polygon:
Interior angle + Exterior angle = 180°
No matter how many sides a polygon has, the sum of all exterior angles is always 360°.
Sum of exterior angles = 360°
Each exterior angle = 360° ÷ n
Example 4: Find the size of each exterior angle of a regular hexagon.
Solution: n = 6
Each = 360° ÷ 6 = 60°
Example 5: Find the size of each interior angle of a regular hexagon.
Solution: Each interior = 180° − 60° = 120°
Example 6: Find the number of sides of a regular polygon whose exterior angle is 40°.
Solution: Each exterior = 360° ÷ n
So, 40° = 360° ÷ n
n = 360° ÷ 40° = 9 sides (nonagon)
| Polygon | Number of Sides (n) | Sum of Interior Angles (n−2)×180° | Each Interior Angle (Regular) | Each Exterior Angle (Regular) |
|---|---|---|---|---|
| Triangle | 3 | 180° | 60° | 120° |
| Quadrilateral | 4 | 360° | 90° | 90° |
| Pentagon | 5 | 540° | 108° | 72° |
| Hexagon | 6 | 720° | 120° | 60° |
| Heptagon | 7 | 900° | 128.6° | 51.4° |
| Octagon | 8 | 1080° | 135° | 45° |
| Nonagon | 9 | 1260° | 140° | 40° |
| Decagon | 10 | 1440° | 144° | 36° |
The angle of elevation is the angle formed when you look upward from a horizontal line to an object that is above the level of your eyes.
It helps us to measure how high an object appears when we look up at it.
Simple meaning:
When you lift your head or eyes to look at something above you (like a bird, a kite, or the top of a building), the angle your eyes make with the ground is called the angle of elevation.
Object (Top of a Building)
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/|
/ |
/θ |
/___|
Observer———Ground Level
θ = Angle of Elevation
In this diagram:
| Term | Meaning |
|---|---|
| Line of Sight | The straight line from the observer’s eye to the object. |
| Horizontal Line | The line parallel to the ground from the observer’s eyes. |
| Vertical Line | The line representing the height of the object (upward). |
Whenever you look up to an object, the ground, your line of sight, and the height of the object form a right-angled triangle.
In that triangle:
In the right-angled triangle:
tan(θ) = Opposite side (height) ÷ Adjacent side (distance)
This formula helps to find:
A boy is standing 20 m away from a tree. The top of the tree is seen at an angle of elevation of 30°. Find the height of the tree.
Top of Tree
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/ |
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Boy 20 m
Angle = 30°
Step 1: Write what we are given.
Distance from boy to tree = 20 m
Angle of elevation = 30°
We are asked to find the height of the tree (h).
Step 2: Recall the trigonometric ratio that connects opposite and adjacent.
Use tan(θ) = opposite ÷ adjacent
Step 3: Substitute the values.
tan(30°) = h ÷ 20
Step 4: From your calculator, tan(30°) = 0.577.
So, 0.577 = h ÷ 20
Step 5: Multiply both sides by 20.
h = 20 × 0.577 = 11.54
Therefore, the height of the tree is about 11.5 m.
A man 1.7 m tall stands 30 m away from a flagpole. The angle of elevation to the top of the pole is 40°. Find the total height of the flagpole.
Top of Flagpole
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/ | (h - 1.7)
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/ |
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Man 30 m
Angle = 40°
Step 1: Write what we know.
Distance = 30 m
Angle = 40°
Man’s eye level = 1.7 m
We are to find the total height of the pole = h.
Step 2: Use the tangent ratio:
tan(40°) = (h - 1.7) ÷ 30
Step 3: From calculator, tan(40°) = 0.8391
Step 4: Substitute.
0.8391 = (h - 1.7) ÷ 30
Step 5: Multiply both sides by 30.
h - 1.7 = 30 × 0.8391 = 25.17
Step 6: Add the man’s height.
h = 25.17 + 1.7 = 26.87
The flagpole is about 26.9 m tall.
A girl stands 10 m away from a building. The top of the building is observed at an angle of 60°. Find the height of the building.
Top of Building
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/ | h
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/ |
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Girl 10 m
Angle = 60°
Step 1: Given:
Distance = 10 m
Angle = 60°
Find h.
Step 2: Formula:
tan(60°) = h ÷ 10
Step 3: From calculator, tan(60°) = 1.732
Step 4: Substitute and solve.
1.732 = h ÷ 10
h = 10 × 1.732 = 17.32
The building is 17.3 m high.
From a point 15 m away from a streetlight, the angle of elevation to the top is 45°. Find the height of the pole.
Top of Pole
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/ | h
/ |
*---*
15 m
Angle = 45°
Step 1: Given: Angle = 45°, Distance = 15 m
Step 2: Formula:
tan(45°) = h ÷ 15
Step 3: tan(45°) = 1
Step 4: Substitute and solve.
1 = h ÷ 15 → h = 15 × 1 = 15
The pole is 15 m high.
A man on one side of a river sees the top of a tree on the other bank at an angle of elevation of 35°. The river is 25 m wide. Find the height of the tree.
Top of Tree
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/ | h
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/ |
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Man 25 m
Angle = 35°
Step 1: Given: Angle = 35°, Distance = 25 m
Step 2: Formula:
tan(35°) = h ÷ 25
Step 3: tan(35°) = 0.7002
Step 4: Solve for h.
h = 25 × 0.7002 = 17.5
The tree is 17.5 m tall.
A helicopter is flying above a building 12 m tall. From the top of the building, the angle of elevation to the helicopter is 50°. If the horizontal distance is 40 m, find how high the helicopter is from the ground.
Helicopter
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/ | (h - 12)
/ |
12m *---*
Building 40 m
Angle = 50°
Step 1: Given:
Height of building = 12 m
Angle = 50°
Distance = 40 m
Find total height h.
Step 2: Use formula:
tan(50°) = (h - 12) ÷ 40
Step 3: tan(50°) = 1.1918
Step 4: Substitute:
1.1918 = (h - 12) ÷ 40
h - 12 = 1.1918 × 40 = 47.67
h = 47.67 + 12 = 59.67
The helicopter is about 59.7 m above the ground.
A flag on a 9 m pole is seen from a point on the ground at an angle of 45°. Find how far the person is standing from the pole.
Top of Flag
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/ | 9 m
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d
Angle = 45°
Step 1: Given: Angle = 45°, Opposite = 9 m
Find the distance (d).
Step 2: Formula:
tan(45°) = 9 ÷ d
Step 3: Since tan(45°) = 1,
1 = 9 ÷ d → d = 9
The person is 9 m away.
A ladder leans against a wall making an angle of 60° with the ground. If the base of the ladder is 4 m away from the wall, how high up does it reach?
Wall
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h | \ Ladder
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4 m
Angle = 60°
Step 1: Given: Angle = 60°, Distance = 4 m
Step 2: Formula:
tan(60°) = h ÷ 4
Step 3: tan(60°) = 1.732
Step 4: Substitute and solve.
1.732 = h ÷ 4 → h = 4 × 1.732 = 6.93
The ladder reaches 6.93 m high on the wall.
A boy standing 50 m away observes the top of a tower at an angle of 28°. Find the height of the tower.
Top of Tower
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/ | h
/ |
/ |
*----*
Boy 50 m
Angle = 28°
Step 1: Given: Angle = 28°, Distance = 50 m
Step 2: Formula:
tan(28°) = h ÷ 50
Step 3: tan(28°) = 0.5317
Step 4: Solve for h.
h = 50 × 0.5317 = 26.6
The tower is 26.6 m tall.
Definition:
The angle of depression is the angle formed between the horizontal line of sight and the line of sight downwards to an object below the observer’s eye level.
In simple words, when you look down at an object, the angle your eyes move downward from the horizontal is called the angle of depression.
Eye level (Horizontal line)
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\ θ /
\ /
\ /
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Car
Here:
We mostly use the tangent formula:
tan(θ) = opposite / adjacent
A girl standing on a 10 m high balcony looks down at a dog. The dog is 15 m away from the base of the building. Find the angle of depression.
Girl
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10m| \
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*----*
15 m
Dog
Step 1: Given
Height = 10 m
Distance = 15 m
Find angle θ.
Step 2: Formula
tan(θ) = opposite / adjacent = 10 / 15
Step 3: Calculate
tan(θ) = 0.6667
Step 4: Find θ
θ = tan⁻¹(0.6667) = 33.7°
Angle of depression = 33.7°
Man
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40m| \
| \25°
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*----*
x (distance)
Step 1: Given
Height = 40 m
Angle = 25°
Find x.
Step 2: Formula
tan(25°) = 40 / x
Step 3: Rearrange
x = 40 / tan(25°)
Step 4: Compute
tan(25°) = 0.4663
x = 40 / 0.4663 = 85.8
Distance = 85.8 m
A man standing on top of a 20 m tall building sees a car on the road at an angle of depression of 45°. Find the distance between the car and the building.
Step 1: Given
Height = 20 m
Angle = 45°
Step 2: Formula
tan(45°) = 20 / x
Step 3: Since tan(45°) = 1:
1 = 20 / x → x = 20
Distance = 20 m
A boy at the top of a tower 50 m high observes a car moving away. When the angle of depression is 60°, find the distance of the car from the base of the tower.
Step 1: Given
Height = 50 m
Angle = 60°
Step 2: Formula
tan(60°) = 50 / x
Step 3: tan(60°) = 1.732
1.732 = 50 / x → x = 50 / 1.732 = 28.9
Distance = 28.9 m
An airplane is flying at an altitude of 500 m. The pilot sees the airport runway at an angle of depression of 10°. Find the horizontal distance to the runway.
Step 1: Given
Height = 500 m
Angle = 10°
Step 2: Formula
tan(10°) = 500 / x
Step 3: tan(10°) = 0.1763
x = 500 / 0.1763 = 2836.6
The runway is about 2837 m away.
A person standing on top of a 60 m hill sees a car at an angle of depression of 35°. Find how far the car is from the hill.
Step 1: tan(35°) = 60 / x
Step 2: x = 60 / tan(35°) = 60 / 0.7002 = 85.7
Distance = 85.7 m
A man stands on a bridge 30 m above the river. He looks down at a boat at an angle of depression of 20°. Find how far the boat is from the base of the bridge.
tan(20°) = 30 / x
x = 30 / 0.3640 = 82.4
Boat is 82.4 m away.
A kite is flying at a height of 25 m. The string makes an angle of depression of 50° from the boy’s hand. Find how far the kite is horizontally from the boy.
tan(50°) = 25 / x
x = 25 / 1.1918 = 21.0
Horizontal distance = 21.0 m
A ship is seen at an angle of depression of 15° from the top of a cliff that is 70 m high. Find the distance of the ship from the base of the cliff.
tan(15°) = 70 / x
x = 70 / 0.2679 = 261.2
Ship is 261.2 m from the cliff.